in linux how do I sort on a field in the text output
In Linux, you can use the sort
command to sort the output of a command based on a specific field. The -k
option is used to specify the field to sort on.
For example, to sort the output of the ls -l
command by the sixth field (the file size), you would use the following command:
ls -l | sort -k 6
If you want to sort in descending order, you can use the -r
option.
ls -l | sort -k 6 -r
You can also use the sort
command on a file, for example if you have a file named 'file.txt' and you want to sort on the second field, you would use this command:
sort -k 2 file.txt
You can also specify the delimiter used in the file with the -t
option, for example if your delimiter is ':' you would use the following command:
sort -t : -k 2 file.txt
can I do a grep on all lines where the 7th colum has a value that is less than 100?
Yes, you can use the grep
command in combination with the awk
command to achieve this. The awk
command can be used to select a specific field and perform a comparison, and then pass the matching lines to grep
for further processing.
For example, to print all lines from a file named 'file.txt' where the 7th column has a value less than 100, you can use the following command:
awk '$7 < 100 { print }' file.txt
You can also combine the awk
command with grep
to filter the lines:
awk '$7 < 100' file.txt | grep "something"
This command will print all the lines where 7th column has value less than 100 and contain "something" string.
You can also use awk
command alone to perform a comparison and print the matching lines without using grep
command.
awk '$7 < 100 && /something/ {print $0}' file.txt
This command will print all the lines where 7th column has value less than 100 and contain "something" string.